8x^(2/3)-7x^(1/3)-1=0

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Solution for 8x^(2/3)-7x^(1/3)-1=0 equation: 


x in (-oo:+oo)

8*x^(2/3)-(7*x^(1/3))-1 = 0

8*x^(2/3)-7*x^(1/3)-1 = 0

t_1 = x^(1/3)

8*t_1^2-7*t_1^1-1 = 0

8*t_1^2-7*t_1-1 = 0

DELTA = (-7)^2-(-1*4*8)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+7)/(2*8) or t_1 = (7-81^(1/2))/(2*8)

t_1 = 1 or t_1 = -1/8

t_1 = -1/8

x^(1/3)+1/8 = 0

1*x^(1/3) = -1/8 // : 1

x^(1/3) = -1/8

( -1/8 < 0 i 1/3 in (0:1) ) => x naleu017Cy do O

t_1 = 1

x^(1/3)-1 = 0

1*x^(1/3) = 1 // : 1

x^(1/3) = 1

x^(1/3) = 1 // ^ 3

x = 1

x = 1

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